"Nathan W. Collier" <MontanaJeeper@aol.com> wrote in message
news:11f0m1rqobb2cca@corp.supernews.com...
> "Stephen Cowell" <scowell@sbcglobal.net> wrote in message
> news:lvXHe.555$646.443@newssvr22.news.prodigy.net. ..
> >> lol reach all you want. if you think its a victory that im not doing
> >> cryo
> >> IN MONTANA then it just shows how pathetic you really are for any type
of
> >> loose victory. :-)
> >
> > No... I think it's a victory when I can point out your
> > silly mistakes... in your own avowed field of 'expertise'.
>
> lol you find a real one (you know, not something youre LYING about, liar)
> and then you might have something. :-)

Do you regard yourself as qualified in cryo? I mean,
are you stupid, or a liar?

> > And you seem to have forgotten that I was
> > chief site tech at a radiotelescope for four years.
> > You see, I *did* cryo
>
> lol now THAT is pathetic. now youre claiming to be a refrigeration guy?
> BUWAHAHA! :-) you couldnt even give me an alternative to replacing an
HMC
> but youre going to claim to be a cryo/refrigeration guy? LOL! :-)

But I *did* give you an alternative to
replacing a head pressure control, Nate...
we all read it. I even specified that lower
ambient was not allowable under the
circumstances.

Go ahead, google back,
see if you can find my early NG posts...
they go back to '92. You'll find NRAO
in there... ever hear of them? The VLBA?
Chief site tech, Nate... four years, my own
$6M site, 82 foot dish to maintain. Two
complete, separate cryo systems, with
5 or 6 refrigerators on each. 15 Kelvins...
that's some cold stuff, Nate... colder than
you'll *ever* work on. I call that *refrigeration*.
Why do you think I've been kicking your ***
so bad? Who do you think you're messing
around with? You're just an HVAC chump.
__
Steve
"i recognize my limitations and
immediately own it (sic). " -- Nate
..

 

"Nathan W. Collier" <MontanaJeeper@aol.com> wrote in message
news:11f0m1rqobb2cca@corp.supernews.com...
> "Stephen Cowell" <scowell@sbcglobal.net> wrote in message
> news:lvXHe.555$646.443@newssvr22.news.prodigy.net. ..
> >> lol reach all you want. if you think its a victory that im not doing
> >> cryo
> >> IN MONTANA then it just shows how pathetic you really are for any type
of
> >> loose victory. :-)
> >
> > No... I think it's a victory when I can point out your
> > silly mistakes... in your own avowed field of 'expertise'.
>
> lol you find a real one (you know, not something youre LYING about, liar)
> and then you might have something. :-)

Do you regard yourself as qualified in cryo? I mean,
are you stupid, or a liar?

> > And you seem to have forgotten that I was
> > chief site tech at a radiotelescope for four years.
> > You see, I *did* cryo
>
> lol now THAT is pathetic. now youre claiming to be a refrigeration guy?
> BUWAHAHA! :-) you couldnt even give me an alternative to replacing an
HMC
> but youre going to claim to be a cryo/refrigeration guy? LOL! :-)

But I *did* give you an alternative to
replacing a head pressure control, Nate...
we all read it. I even specified that lower
ambient was not allowable under the
circumstances.

Go ahead, google back,
see if you can find my early NG posts...
they go back to '92. You'll find NRAO
in there... ever hear of them? The VLBA?
Chief site tech, Nate... four years, my own
$6M site, 82 foot dish to maintain. Two
complete, separate cryo systems, with
5 or 6 refrigerators on each. 15 Kelvins...
that's some cold stuff, Nate... colder than
you'll *ever* work on. I call that *refrigeration*.
Why do you think I've been kicking your ***
so bad? Who do you think you're messing
around with? You're just an HVAC chump.
__
Steve
"i recognize my limitations and
immediately own it (sic). " -- Nate
..

 

"Nathan W. Collier" <MontanaJeeper@aol.com> wrote in message
news:11f0m1rqobb2cca@corp.supernews.com...
> "Stephen Cowell" <scowell@sbcglobal.net> wrote in message
> news:lvXHe.555$646.443@newssvr22.news.prodigy.net. ..
> >> lol reach all you want. if you think its a victory that im not doing
> >> cryo
> >> IN MONTANA then it just shows how pathetic you really are for any type
of
> >> loose victory. :-)
> >
> > No... I think it's a victory when I can point out your
> > silly mistakes... in your own avowed field of 'expertise'.
>
> lol you find a real one (you know, not something youre LYING about, liar)
> and then you might have something. :-)

Do you regard yourself as qualified in cryo? I mean,
are you stupid, or a liar?

> > And you seem to have forgotten that I was
> > chief site tech at a radiotelescope for four years.
> > You see, I *did* cryo
>
> lol now THAT is pathetic. now youre claiming to be a refrigeration guy?
> BUWAHAHA! :-) you couldnt even give me an alternative to replacing an
HMC
> but youre going to claim to be a cryo/refrigeration guy? LOL! :-)

But I *did* give you an alternative to
replacing a head pressure control, Nate...
we all read it. I even specified that lower
ambient was not allowable under the
circumstances.

Go ahead, google back,
see if you can find my early NG posts...
they go back to '92. You'll find NRAO
in there... ever hear of them? The VLBA?
Chief site tech, Nate... four years, my own
$6M site, 82 foot dish to maintain. Two
complete, separate cryo systems, with
5 or 6 refrigerators on each. 15 Kelvins...
that's some cold stuff, Nate... colder than
you'll *ever* work on. I call that *refrigeration*.
Why do you think I've been kicking your ***
so bad? Who do you think you're messing
around with? You're just an HVAC chump.
__
Steve
"i recognize my limitations and
immediately own it (sic). " -- Nate
..

 

"L.W. (ßill) ------ III" <----------@***.net> wrote in message
news:42F04534.497151B@***.net...
> Stephen Cowell wrote:
> >
> > You continue to top yourself! Are you not aware
> > of the formula for a regular cylinder? Do you not
> > agree that an area times a length gives you your
> > cubic dimension? What about good old Mr.
> > What'sHisName? Didn't he teach you about this?
> > You claimed to have 'gone through Calculus'!
> > Like corn through a goose, I replied... apropos.
> >
> > Here's another hint... the liquid level forms
> > a chord across the end, parallel to a diameter
> > of the circular face. Draw a line from the
> > center of the circular face to the edge of the
> > tank where the liquid level is... a radius line.
> > It should all be clear now... if you can figure
> > out the area of a piece of 2D pie!

> Stevie, you bought the analogy of sticking a tank and said half full was
> half the tank, true, but your were heading for if I dropped the stick
> and it came up a quarter, that quarter, would be more like an eighth
> tank.
> God Bless America, ßill O|||||||O

You're way behind, Bill... catch up with the
rest of the class.

We just covered two hint/facts:
1) We know the half-full condition, since
it's easy to construct.

2) We considered that the liquid always forms
a level line... considering the diameter of the
circular face parallel to this line, we can construct
a radius line from the center of the circular face
to the edge of the liquid level. This final picture,
with the diameter, the liquid level, and the radius
line, should have been enough for an astute person
to take it the rest of the way.

Let's elaborate on that last picture... add a diameter
perpendicular to the half-full diameter. Now you
can see the triangle formed by the liquid level,
the radius line, and the vertical diameter. We know
two sides and an angle of this triangle, so we know
all we need to figure all sides and angles. We can use
he Pythagorean Theorem to find the unknown side...
A^2 + B^2 = C^2. We can find the area using
1/2 (base * height).

Now we need the area of the pie-shaped piece
on top (or bottom, for the more-than-half-full
case) of the triangle. Since we know the angle
of the wedge (arcsin (base/hyp)) we can take
the ratio of this to 360 degrees, times the area
of the circular face, which we know since we
know the radius of the tank. All the pieces are
now in place.

For the less-than-half full case:
Half he area of the circular face minus the quantity
twice the area of the triangle plus twice the area
of the pie wedge

For the more-than-half-full case:
Half the area of the circular face, plus twice the area of
the triangle, plus twice the area of the pie wedge.

Then times the length. Easy, wasn't it?
__
Steve
"i recognize my limitations and
immediately own it (sic). " -- Nate
..

 

"L.W. (ßill) ------ III" <----------@***.net> wrote in message
news:42F04534.497151B@***.net...
> Stephen Cowell wrote:
> >
> > You continue to top yourself! Are you not aware
> > of the formula for a regular cylinder? Do you not
> > agree that an area times a length gives you your
> > cubic dimension? What about good old Mr.
> > What'sHisName? Didn't he teach you about this?
> > You claimed to have 'gone through Calculus'!
> > Like corn through a goose, I replied... apropos.
> >
> > Here's another hint... the liquid level forms
> > a chord across the end, parallel to a diameter
> > of the circular face. Draw a line from the
> > center of the circular face to the edge of the
> > tank where the liquid level is... a radius line.
> > It should all be clear now... if you can figure
> > out the area of a piece of 2D pie!

> Stevie, you bought the analogy of sticking a tank and said half full was
> half the tank, true, but your were heading for if I dropped the stick
> and it came up a quarter, that quarter, would be more like an eighth
> tank.
> God Bless America, ßill O|||||||O

You're way behind, Bill... catch up with the
rest of the class.

We just covered two hint/facts:
1) We know the half-full condition, since
it's easy to construct.

2) We considered that the liquid always forms
a level line... considering the diameter of the
circular face parallel to this line, we can construct
a radius line from the center of the circular face
to the edge of the liquid level. This final picture,
with the diameter, the liquid level, and the radius
line, should have been enough for an astute person
to take it the rest of the way.

Let's elaborate on that last picture... add a diameter
perpendicular to the half-full diameter. Now you
can see the triangle formed by the liquid level,
the radius line, and the vertical diameter. We know
two sides and an angle of this triangle, so we know
all we need to figure all sides and angles. We can use
he Pythagorean Theorem to find the unknown side...
A^2 + B^2 = C^2. We can find the area using
1/2 (base * height).

Now we need the area of the pie-shaped piece
on top (or bottom, for the more-than-half-full
case) of the triangle. Since we know the angle
of the wedge (arcsin (base/hyp)) we can take
the ratio of this to 360 degrees, times the area
of the circular face, which we know since we
know the radius of the tank. All the pieces are
now in place.

For the less-than-half full case:
Half he area of the circular face minus the quantity
twice the area of the triangle plus twice the area
of the pie wedge

For the more-than-half-full case:
Half the area of the circular face, plus twice the area of
the triangle, plus twice the area of the pie wedge.

Then times the length. Easy, wasn't it?
__
Steve
"i recognize my limitations and
immediately own it (sic). " -- Nate
..

 

"L.W. (ßill) ------ III" <----------@***.net> wrote in message
news:42F04534.497151B@***.net...
> Stephen Cowell wrote:
> >
> > You continue to top yourself! Are you not aware
> > of the formula for a regular cylinder? Do you not
> > agree that an area times a length gives you your
> > cubic dimension? What about good old Mr.
> > What'sHisName? Didn't he teach you about this?
> > You claimed to have 'gone through Calculus'!
> > Like corn through a goose, I replied... apropos.
> >
> > Here's another hint... the liquid level forms
> > a chord across the end, parallel to a diameter
> > of the circular face. Draw a line from the
> > center of the circular face to the edge of the
> > tank where the liquid level is... a radius line.
> > It should all be clear now... if you can figure
> > out the area of a piece of 2D pie!

> Stevie, you bought the analogy of sticking a tank and said half full was
> half the tank, true, but your were heading for if I dropped the stick
> and it came up a quarter, that quarter, would be more like an eighth
> tank.
> God Bless America, ßill O|||||||O

You're way behind, Bill... catch up with the
rest of the class.

We just covered two hint/facts:
1) We know the half-full condition, since
it's easy to construct.

2) We considered that the liquid always forms
a level line... considering the diameter of the
circular face parallel to this line, we can construct
a radius line from the center of the circular face
to the edge of the liquid level. This final picture,
with the diameter, the liquid level, and the radius
line, should have been enough for an astute person
to take it the rest of the way.

Let's elaborate on that last picture... add a diameter
perpendicular to the half-full diameter. Now you
can see the triangle formed by the liquid level,
the radius line, and the vertical diameter. We know
two sides and an angle of this triangle, so we know
all we need to figure all sides and angles. We can use
he Pythagorean Theorem to find the unknown side...
A^2 + B^2 = C^2. We can find the area using
1/2 (base * height).

Now we need the area of the pie-shaped piece
on top (or bottom, for the more-than-half-full
case) of the triangle. Since we know the angle
of the wedge (arcsin (base/hyp)) we can take
the ratio of this to 360 degrees, times the area
of the circular face, which we know since we
know the radius of the tank. All the pieces are
now in place.

For the less-than-half full case:
Half he area of the circular face minus the quantity
twice the area of the triangle plus twice the area
of the pie wedge

For the more-than-half-full case:
Half the area of the circular face, plus twice the area of
the triangle, plus twice the area of the pie wedge.

Then times the length. Easy, wasn't it?
__
Steve
"i recognize my limitations and
immediately own it (sic). " -- Nate
..

 

"L.W. (ßill) ------ III" <----------@***.net> wrote in message
news:42F04534.497151B@***.net...
> Stephen Cowell wrote:
> >
> > You continue to top yourself! Are you not aware
> > of the formula for a regular cylinder? Do you not
> > agree that an area times a length gives you your
> > cubic dimension? What about good old Mr.
> > What'sHisName? Didn't he teach you about this?
> > You claimed to have 'gone through Calculus'!
> > Like corn through a goose, I replied... apropos.
> >
> > Here's another hint... the liquid level forms
> > a chord across the end, parallel to a diameter
> > of the circular face. Draw a line from the
> > center of the circular face to the edge of the
> > tank where the liquid level is... a radius line.
> > It should all be clear now... if you can figure
> > out the area of a piece of 2D pie!

> Stevie, you bought the analogy of sticking a tank and said half full was
> half the tank, true, but your were heading for if I dropped the stick
> and it came up a quarter, that quarter, would be more like an eighth
> tank.
> God Bless America, ßill O|||||||O

You're way behind, Bill... catch up with the
rest of the class.

We just covered two hint/facts:
1) We know the half-full condition, since
it's easy to construct.

2) We considered that the liquid always forms
a level line... considering the diameter of the
circular face parallel to this line, we can construct
a radius line from the center of the circular face
to the edge of the liquid level. This final picture,
with the diameter, the liquid level, and the radius
line, should have been enough for an astute person
to take it the rest of the way.

Let's elaborate on that last picture... add a diameter
perpendicular to the half-full diameter. Now you
can see the triangle formed by the liquid level,
the radius line, and the vertical diameter. We know
two sides and an angle of this triangle, so we know
all we need to figure all sides and angles. We can use
he Pythagorean Theorem to find the unknown side...
A^2 + B^2 = C^2. We can find the area using
1/2 (base * height).

Now we need the area of the pie-shaped piece
on top (or bottom, for the more-than-half-full
case) of the triangle. Since we know the angle
of the wedge (arcsin (base/hyp)) we can take
the ratio of this to 360 degrees, times the area
of the circular face, which we know since we
know the radius of the tank. All the pieces are
now in place.

For the less-than-half full case:
Half he area of the circular face minus the quantity
twice the area of the triangle plus twice the area
of the pie wedge

For the more-than-half-full case:
Half the area of the circular face, plus twice the area of
the triangle, plus twice the area of the pie wedge.

Then times the length. Easy, wasn't it?
__
Steve
"i recognize my limitations and
immediately own it (sic). " -- Nate
..

 

"L.W. (ßill) ------ III" <----------@***.net> wrote in message
news:42F04A39.D79262AC@***.net...
....

> 360 - 2(90 - arcsin [(r-h)/r])
> ------------------------------- (Pi)r^2 + (r-h)Sqrt (2rh - h^2)
> 360
>
> God Bless America, ßill O|||||||O

But you're just pasting some Google stuff, like
you always do... I thought you went through
Calculus! You do remember the specifics of
the challenge... no Google! Even a chimpanzee
can wave a book over his head... doesn't give
him the understanding in the book.

You lose!
__
Steve
"i recognize my limitations and
immediately own it (sic)."... Nate
..

 

"L.W. (ßill) ------ III" <----------@***.net> wrote in message
news:42F04A39.D79262AC@***.net...
....

> 360 - 2(90 - arcsin [(r-h)/r])
> ------------------------------- (Pi)r^2 + (r-h)Sqrt (2rh - h^2)
> 360
>
> God Bless America, ßill O|||||||O

But you're just pasting some Google stuff, like
you always do... I thought you went through
Calculus! You do remember the specifics of
the challenge... no Google! Even a chimpanzee
can wave a book over his head... doesn't give
him the understanding in the book.

You lose!
__
Steve
"i recognize my limitations and
immediately own it (sic)."... Nate
..

 

"L.W. (ßill) ------ III" <----------@***.net> wrote in message
news:42F04A39.D79262AC@***.net...
....

> 360 - 2(90 - arcsin [(r-h)/r])
> ------------------------------- (Pi)r^2 + (r-h)Sqrt (2rh - h^2)
> 360
>
> God Bless America, ßill O|||||||O

But you're just pasting some Google stuff, like
you always do... I thought you went through
Calculus! You do remember the specifics of
the challenge... no Google! Even a chimpanzee
can wave a book over his head... doesn't give
him the understanding in the book.

You lose!
__
Steve
"i recognize my limitations and
immediately own it (sic)."... Nate
..