Torque/HP curves
02-26-2006, 11:41 AM
#41
Guest
Posts: n/a
Re: Torque/HP curves
Hi Dave,
You originally said: "Power and torque curves always cross at 5252
rpm!" That's Revolution Per Minute, not 5252 feet. Most carburated
engines like your wagon can't get near 5252 RPM without both a four
barrel and performance cam near three hundred degrees.
Yes, using a wheel dynamometer we measure the torque and
mathematically computer horsepower from it.
Circumference of a circle equals Pi times the Diameter.
God Bless America, Bill O|||||||O
mailto:-------------------- http://www.----------.com/
Dave Milne wrote:
>
> Hi Bill,
>
> No, I meant that power and torque are mathematically linked..
>
> Torque = Force x Radius
> Power = Force x Distance / Time
>
> Given that the definition of 1 Hp is the ability to of a horse to move
> 33,000 lb ft / lb in a minute,
> we can divide that by the circumference of a circle (2 x pi x r) to get the
> number
> of times a horse could move 33,000lb round a circle of diameter 1 foot in a
> minute.
> That is 33,000 / (2 x 3.1415926 x 1) = 5252.
>
> So that's true for any engine.
>
> Dave
>
> "L.W. (ßill) ------ III" <----------@***.net> wrote in message
> news:43FF8D4F.F4B53BAC@***.net...
> > Hi Dave,
> > That would be a very high performance engine with over 330 degrees
> > of cam duration and wouldn't idle worth a sh*t below 1800 RPMs, like
> > this Chevy small block: http://stunmun0.tripod.com/index/hp.jpg Most of
> > us are less than three grand, like this Kraut V6:
> >
> http://www.worldcarfans.com/news.cfm...ml/country/gcf
> > God Bless America, Bill O|||||||O
> > mailto:-------------------- http://www.----------.com/
> >
> > Dave Milne wrote:
> > >
> > > Hang on a mo, Power and torque curves always cross at 5252 rpm !
> > >
> > > Dave Milne, Scotland
You originally said: "Power and torque curves always cross at 5252
rpm!" That's Revolution Per Minute, not 5252 feet. Most carburated
engines like your wagon can't get near 5252 RPM without both a four
barrel and performance cam near three hundred degrees.
Yes, using a wheel dynamometer we measure the torque and
mathematically computer horsepower from it.
Circumference of a circle equals Pi times the Diameter.
God Bless America, Bill O|||||||O
mailto:-------------------- http://www.----------.com/
Dave Milne wrote:
>
> Hi Bill,
>
> No, I meant that power and torque are mathematically linked..
>
> Torque = Force x Radius
> Power = Force x Distance / Time
>
> Given that the definition of 1 Hp is the ability to of a horse to move
> 33,000 lb ft / lb in a minute,
> we can divide that by the circumference of a circle (2 x pi x r) to get the
> number
> of times a horse could move 33,000lb round a circle of diameter 1 foot in a
> minute.
> That is 33,000 / (2 x 3.1415926 x 1) = 5252.
>
> So that's true for any engine.
>
> Dave
>
> "L.W. (ßill) ------ III" <----------@***.net> wrote in message
> news:43FF8D4F.F4B53BAC@***.net...
> > Hi Dave,
> > That would be a very high performance engine with over 330 degrees
> > of cam duration and wouldn't idle worth a sh*t below 1800 RPMs, like
> > this Chevy small block: http://stunmun0.tripod.com/index/hp.jpg Most of
> > us are less than three grand, like this Kraut V6:
> >
> http://www.worldcarfans.com/news.cfm...ml/country/gcf
> > God Bless America, Bill O|||||||O
> > mailto:-------------------- http://www.----------.com/
> >
> > Dave Milne wrote:
> > >
> > > Hang on a mo, Power and torque curves always cross at 5252 rpm !
> > >
> > > Dave Milne, Scotland
02-26-2006, 02:05 PM
#42
Guest
Posts: n/a
Re: Torque/HP curves
Read it carefully - I said 5252 rpm. Although I made a small mistake - I
said a circle of 1 foot diameter and I meant a circle of 1 foot radius.
As to whether an engine will rev that high or what type of cam it uses to
get there is immaterial ; it just means that the power and torque curves
WILL NOT cross each other.
Dave
"L.W. (ßill) ------ III" <----------@***.net> wrote in message
news:4401DA3C.852246B7@***.net...
> Hi Dave,
> You originally said: "Power and torque curves always cross at 5252
> rpm!" That's Revolution Per Minute, not 5252 feet. Most carburated
> engines like your wagon can't get near 5252 RPM without both a four
> barrel and performance cam near three hundred degrees.
> Yes, using a wheel dynamometer we measure the torque and
> mathematically computer horsepower from it.
> Circumference of a circle equals Pi times the Diameter.
> God Bless America, Bill O|||||||O
> mailto:-------------------- http://www.----------.com/
>
> Dave Milne wrote:
> >
> > Hi Bill,
> >
> > No, I meant that power and torque are mathematically linked..
> >
> > Torque = Force x Radius
> > Power = Force x Distance / Time
> >
> > Given that the definition of 1 Hp is the ability to of a horse to move
> > 33,000 lb ft / lb in a minute,
> > we can divide that by the circumference of a circle (2 x pi x r) to get
the
> > number
> > of times a horse could move 33,000lb round a circle of diameter 1 foot
in a
> > minute.
> > That is 33,000 / (2 x 3.1415926 x 1) = 5252.
> >
> > So that's true for any engine.
> >
> > Dave
> >
> > "L.W. (ßill) ------ III" <----------@***.net> wrote in message
> > news:43FF8D4F.F4B53BAC@***.net...
> > > Hi Dave,
> > > That would be a very high performance engine with over 330
degrees
> > > of cam duration and wouldn't idle worth a sh*t below 1800 RPMs, like
> > > this Chevy small block: http://stunmun0.tripod.com/index/hp.jpg Most
of
> > > us are less than three grand, like this Kraut V6:
> > >
> >
http://www.worldcarfans.com/news.cfm...ml/country/gcf
> > > God Bless America, Bill O|||||||O
> > > mailto:-------------------- http://www.----------.com/
> > >
> > > Dave Milne wrote:
> > > >
> > > > Hang on a mo, Power and torque curves always cross at 5252 rpm !
> > > >
> > > > Dave Milne, Scotland
said a circle of 1 foot diameter and I meant a circle of 1 foot radius.
As to whether an engine will rev that high or what type of cam it uses to
get there is immaterial ; it just means that the power and torque curves
WILL NOT cross each other.
Dave
"L.W. (ßill) ------ III" <----------@***.net> wrote in message
news:4401DA3C.852246B7@***.net...
> Hi Dave,
> You originally said: "Power and torque curves always cross at 5252
> rpm!" That's Revolution Per Minute, not 5252 feet. Most carburated
> engines like your wagon can't get near 5252 RPM without both a four
> barrel and performance cam near three hundred degrees.
> Yes, using a wheel dynamometer we measure the torque and
> mathematically computer horsepower from it.
> Circumference of a circle equals Pi times the Diameter.
> God Bless America, Bill O|||||||O
> mailto:-------------------- http://www.----------.com/
>
> Dave Milne wrote:
> >
> > Hi Bill,
> >
> > No, I meant that power and torque are mathematically linked..
> >
> > Torque = Force x Radius
> > Power = Force x Distance / Time
> >
> > Given that the definition of 1 Hp is the ability to of a horse to move
> > 33,000 lb ft / lb in a minute,
> > we can divide that by the circumference of a circle (2 x pi x r) to get
the
> > number
> > of times a horse could move 33,000lb round a circle of diameter 1 foot
in a
> > minute.
> > That is 33,000 / (2 x 3.1415926 x 1) = 5252.
> >
> > So that's true for any engine.
> >
> > Dave
> >
> > "L.W. (ßill) ------ III" <----------@***.net> wrote in message
> > news:43FF8D4F.F4B53BAC@***.net...
> > > Hi Dave,
> > > That would be a very high performance engine with over 330
degrees
> > > of cam duration and wouldn't idle worth a sh*t below 1800 RPMs, like
> > > this Chevy small block: http://stunmun0.tripod.com/index/hp.jpg Most
of
> > > us are less than three grand, like this Kraut V6:
> > >
> >
http://www.worldcarfans.com/news.cfm...ml/country/gcf
> > > God Bless America, Bill O|||||||O
> > > mailto:-------------------- http://www.----------.com/
> > >
> > > Dave Milne wrote:
> > > >
> > > > Hang on a mo, Power and torque curves always cross at 5252 rpm !
> > > >
> > > > Dave Milne, Scotland
02-26-2006, 02:05 PM
#43
Guest
Posts: n/a
Re: Torque/HP curves
Read it carefully - I said 5252 rpm. Although I made a small mistake - I
said a circle of 1 foot diameter and I meant a circle of 1 foot radius.
As to whether an engine will rev that high or what type of cam it uses to
get there is immaterial ; it just means that the power and torque curves
WILL NOT cross each other.
Dave
"L.W. (ßill) ------ III" <----------@***.net> wrote in message
news:4401DA3C.852246B7@***.net...
> Hi Dave,
> You originally said: "Power and torque curves always cross at 5252
> rpm!" That's Revolution Per Minute, not 5252 feet. Most carburated
> engines like your wagon can't get near 5252 RPM without both a four
> barrel and performance cam near three hundred degrees.
> Yes, using a wheel dynamometer we measure the torque and
> mathematically computer horsepower from it.
> Circumference of a circle equals Pi times the Diameter.
> God Bless America, Bill O|||||||O
> mailto:-------------------- http://www.----------.com/
>
> Dave Milne wrote:
> >
> > Hi Bill,
> >
> > No, I meant that power and torque are mathematically linked..
> >
> > Torque = Force x Radius
> > Power = Force x Distance / Time
> >
> > Given that the definition of 1 Hp is the ability to of a horse to move
> > 33,000 lb ft / lb in a minute,
> > we can divide that by the circumference of a circle (2 x pi x r) to get
the
> > number
> > of times a horse could move 33,000lb round a circle of diameter 1 foot
in a
> > minute.
> > That is 33,000 / (2 x 3.1415926 x 1) = 5252.
> >
> > So that's true for any engine.
> >
> > Dave
> >
> > "L.W. (ßill) ------ III" <----------@***.net> wrote in message
> > news:43FF8D4F.F4B53BAC@***.net...
> > > Hi Dave,
> > > That would be a very high performance engine with over 330
degrees
> > > of cam duration and wouldn't idle worth a sh*t below 1800 RPMs, like
> > > this Chevy small block: http://stunmun0.tripod.com/index/hp.jpg Most
of
> > > us are less than three grand, like this Kraut V6:
> > >
> >
http://www.worldcarfans.com/news.cfm...ml/country/gcf
> > > God Bless America, Bill O|||||||O
> > > mailto:-------------------- http://www.----------.com/
> > >
> > > Dave Milne wrote:
> > > >
> > > > Hang on a mo, Power and torque curves always cross at 5252 rpm !
> > > >
> > > > Dave Milne, Scotland
said a circle of 1 foot diameter and I meant a circle of 1 foot radius.
As to whether an engine will rev that high or what type of cam it uses to
get there is immaterial ; it just means that the power and torque curves
WILL NOT cross each other.
Dave
"L.W. (ßill) ------ III" <----------@***.net> wrote in message
news:4401DA3C.852246B7@***.net...
> Hi Dave,
> You originally said: "Power and torque curves always cross at 5252
> rpm!" That's Revolution Per Minute, not 5252 feet. Most carburated
> engines like your wagon can't get near 5252 RPM without both a four
> barrel and performance cam near three hundred degrees.
> Yes, using a wheel dynamometer we measure the torque and
> mathematically computer horsepower from it.
> Circumference of a circle equals Pi times the Diameter.
> God Bless America, Bill O|||||||O
> mailto:-------------------- http://www.----------.com/
>
> Dave Milne wrote:
> >
> > Hi Bill,
> >
> > No, I meant that power and torque are mathematically linked..
> >
> > Torque = Force x Radius
> > Power = Force x Distance / Time
> >
> > Given that the definition of 1 Hp is the ability to of a horse to move
> > 33,000 lb ft / lb in a minute,
> > we can divide that by the circumference of a circle (2 x pi x r) to get
the
> > number
> > of times a horse could move 33,000lb round a circle of diameter 1 foot
in a
> > minute.
> > That is 33,000 / (2 x 3.1415926 x 1) = 5252.
> >
> > So that's true for any engine.
> >
> > Dave
> >
> > "L.W. (ßill) ------ III" <----------@***.net> wrote in message
> > news:43FF8D4F.F4B53BAC@***.net...
> > > Hi Dave,
> > > That would be a very high performance engine with over 330
degrees
> > > of cam duration and wouldn't idle worth a sh*t below 1800 RPMs, like
> > > this Chevy small block: http://stunmun0.tripod.com/index/hp.jpg Most
of
> > > us are less than three grand, like this Kraut V6:
> > >
> >
http://www.worldcarfans.com/news.cfm...ml/country/gcf
> > > God Bless America, Bill O|||||||O
> > > mailto:-------------------- http://www.----------.com/
> > >
> > > Dave Milne wrote:
> > > >
> > > > Hang on a mo, Power and torque curves always cross at 5252 rpm !
> > > >
> > > > Dave Milne, Scotland
02-26-2006, 02:05 PM
#44
Guest
Posts: n/a
Re: Torque/HP curves
Read it carefully - I said 5252 rpm. Although I made a small mistake - I
said a circle of 1 foot diameter and I meant a circle of 1 foot radius.
As to whether an engine will rev that high or what type of cam it uses to
get there is immaterial ; it just means that the power and torque curves
WILL NOT cross each other.
Dave
"L.W. (ßill) ------ III" <----------@***.net> wrote in message
news:4401DA3C.852246B7@***.net...
> Hi Dave,
> You originally said: "Power and torque curves always cross at 5252
> rpm!" That's Revolution Per Minute, not 5252 feet. Most carburated
> engines like your wagon can't get near 5252 RPM without both a four
> barrel and performance cam near three hundred degrees.
> Yes, using a wheel dynamometer we measure the torque and
> mathematically computer horsepower from it.
> Circumference of a circle equals Pi times the Diameter.
> God Bless America, Bill O|||||||O
> mailto:-------------------- http://www.----------.com/
>
> Dave Milne wrote:
> >
> > Hi Bill,
> >
> > No, I meant that power and torque are mathematically linked..
> >
> > Torque = Force x Radius
> > Power = Force x Distance / Time
> >
> > Given that the definition of 1 Hp is the ability to of a horse to move
> > 33,000 lb ft / lb in a minute,
> > we can divide that by the circumference of a circle (2 x pi x r) to get
the
> > number
> > of times a horse could move 33,000lb round a circle of diameter 1 foot
in a
> > minute.
> > That is 33,000 / (2 x 3.1415926 x 1) = 5252.
> >
> > So that's true for any engine.
> >
> > Dave
> >
> > "L.W. (ßill) ------ III" <----------@***.net> wrote in message
> > news:43FF8D4F.F4B53BAC@***.net...
> > > Hi Dave,
> > > That would be a very high performance engine with over 330
degrees
> > > of cam duration and wouldn't idle worth a sh*t below 1800 RPMs, like
> > > this Chevy small block: http://stunmun0.tripod.com/index/hp.jpg Most
of
> > > us are less than three grand, like this Kraut V6:
> > >
> >
http://www.worldcarfans.com/news.cfm...ml/country/gcf
> > > God Bless America, Bill O|||||||O
> > > mailto:-------------------- http://www.----------.com/
> > >
> > > Dave Milne wrote:
> > > >
> > > > Hang on a mo, Power and torque curves always cross at 5252 rpm !
> > > >
> > > > Dave Milne, Scotland
said a circle of 1 foot diameter and I meant a circle of 1 foot radius.
As to whether an engine will rev that high or what type of cam it uses to
get there is immaterial ; it just means that the power and torque curves
WILL NOT cross each other.
Dave
"L.W. (ßill) ------ III" <----------@***.net> wrote in message
news:4401DA3C.852246B7@***.net...
> Hi Dave,
> You originally said: "Power and torque curves always cross at 5252
> rpm!" That's Revolution Per Minute, not 5252 feet. Most carburated
> engines like your wagon can't get near 5252 RPM without both a four
> barrel and performance cam near three hundred degrees.
> Yes, using a wheel dynamometer we measure the torque and
> mathematically computer horsepower from it.
> Circumference of a circle equals Pi times the Diameter.
> God Bless America, Bill O|||||||O
> mailto:-------------------- http://www.----------.com/
>
> Dave Milne wrote:
> >
> > Hi Bill,
> >
> > No, I meant that power and torque are mathematically linked..
> >
> > Torque = Force x Radius
> > Power = Force x Distance / Time
> >
> > Given that the definition of 1 Hp is the ability to of a horse to move
> > 33,000 lb ft / lb in a minute,
> > we can divide that by the circumference of a circle (2 x pi x r) to get
the
> > number
> > of times a horse could move 33,000lb round a circle of diameter 1 foot
in a
> > minute.
> > That is 33,000 / (2 x 3.1415926 x 1) = 5252.
> >
> > So that's true for any engine.
> >
> > Dave
> >
> > "L.W. (ßill) ------ III" <----------@***.net> wrote in message
> > news:43FF8D4F.F4B53BAC@***.net...
> > > Hi Dave,
> > > That would be a very high performance engine with over 330
degrees
> > > of cam duration and wouldn't idle worth a sh*t below 1800 RPMs, like
> > > this Chevy small block: http://stunmun0.tripod.com/index/hp.jpg Most
of
> > > us are less than three grand, like this Kraut V6:
> > >
> >
http://www.worldcarfans.com/news.cfm...ml/country/gcf
> > > God Bless America, Bill O|||||||O
> > > mailto:-------------------- http://www.----------.com/
> > >
> > > Dave Milne wrote:
> > > >
> > > > Hang on a mo, Power and torque curves always cross at 5252 rpm !
> > > >
> > > > Dave Milne, Scotland
02-26-2006, 02:05 PM
#45
Guest
Posts: n/a
Re: Torque/HP curves
Read it carefully - I said 5252 rpm. Although I made a small mistake - I
said a circle of 1 foot diameter and I meant a circle of 1 foot radius.
As to whether an engine will rev that high or what type of cam it uses to
get there is immaterial ; it just means that the power and torque curves
WILL NOT cross each other.
Dave
"L.W. (ßill) ------ III" <----------@***.net> wrote in message
news:4401DA3C.852246B7@***.net...
> Hi Dave,
> You originally said: "Power and torque curves always cross at 5252
> rpm!" That's Revolution Per Minute, not 5252 feet. Most carburated
> engines like your wagon can't get near 5252 RPM without both a four
> barrel and performance cam near three hundred degrees.
> Yes, using a wheel dynamometer we measure the torque and
> mathematically computer horsepower from it.
> Circumference of a circle equals Pi times the Diameter.
> God Bless America, Bill O|||||||O
> mailto:-------------------- http://www.----------.com/
>
> Dave Milne wrote:
> >
> > Hi Bill,
> >
> > No, I meant that power and torque are mathematically linked..
> >
> > Torque = Force x Radius
> > Power = Force x Distance / Time
> >
> > Given that the definition of 1 Hp is the ability to of a horse to move
> > 33,000 lb ft / lb in a minute,
> > we can divide that by the circumference of a circle (2 x pi x r) to get
the
> > number
> > of times a horse could move 33,000lb round a circle of diameter 1 foot
in a
> > minute.
> > That is 33,000 / (2 x 3.1415926 x 1) = 5252.
> >
> > So that's true for any engine.
> >
> > Dave
> >
> > "L.W. (ßill) ------ III" <----------@***.net> wrote in message
> > news:43FF8D4F.F4B53BAC@***.net...
> > > Hi Dave,
> > > That would be a very high performance engine with over 330
degrees
> > > of cam duration and wouldn't idle worth a sh*t below 1800 RPMs, like
> > > this Chevy small block: http://stunmun0.tripod.com/index/hp.jpg Most
of
> > > us are less than three grand, like this Kraut V6:
> > >
> >
http://www.worldcarfans.com/news.cfm...ml/country/gcf
> > > God Bless America, Bill O|||||||O
> > > mailto:-------------------- http://www.----------.com/
> > >
> > > Dave Milne wrote:
> > > >
> > > > Hang on a mo, Power and torque curves always cross at 5252 rpm !
> > > >
> > > > Dave Milne, Scotland
said a circle of 1 foot diameter and I meant a circle of 1 foot radius.
As to whether an engine will rev that high or what type of cam it uses to
get there is immaterial ; it just means that the power and torque curves
WILL NOT cross each other.
Dave
"L.W. (ßill) ------ III" <----------@***.net> wrote in message
news:4401DA3C.852246B7@***.net...
> Hi Dave,
> You originally said: "Power and torque curves always cross at 5252
> rpm!" That's Revolution Per Minute, not 5252 feet. Most carburated
> engines like your wagon can't get near 5252 RPM without both a four
> barrel and performance cam near three hundred degrees.
> Yes, using a wheel dynamometer we measure the torque and
> mathematically computer horsepower from it.
> Circumference of a circle equals Pi times the Diameter.
> God Bless America, Bill O|||||||O
> mailto:-------------------- http://www.----------.com/
>
> Dave Milne wrote:
> >
> > Hi Bill,
> >
> > No, I meant that power and torque are mathematically linked..
> >
> > Torque = Force x Radius
> > Power = Force x Distance / Time
> >
> > Given that the definition of 1 Hp is the ability to of a horse to move
> > 33,000 lb ft / lb in a minute,
> > we can divide that by the circumference of a circle (2 x pi x r) to get
the
> > number
> > of times a horse could move 33,000lb round a circle of diameter 1 foot
in a
> > minute.
> > That is 33,000 / (2 x 3.1415926 x 1) = 5252.
> >
> > So that's true for any engine.
> >
> > Dave
> >
> > "L.W. (ßill) ------ III" <----------@***.net> wrote in message
> > news:43FF8D4F.F4B53BAC@***.net...
> > > Hi Dave,
> > > That would be a very high performance engine with over 330
degrees
> > > of cam duration and wouldn't idle worth a sh*t below 1800 RPMs, like
> > > this Chevy small block: http://stunmun0.tripod.com/index/hp.jpg Most
of
> > > us are less than three grand, like this Kraut V6:
> > >
> >
http://www.worldcarfans.com/news.cfm...ml/country/gcf
> > > God Bless America, Bill O|||||||O
> > > mailto:-------------------- http://www.----------.com/
> > >
> > > Dave Milne wrote:
> > > >
> > > > Hang on a mo, Power and torque curves always cross at 5252 rpm !
> > > >
> > > > Dave Milne, Scotland
02-26-2006, 03:27 PM
#46
Guest
Posts: n/a
Re: Torque/HP curves
"immaterial"! Make a graph where the torque and horsepower do not
cross.
God Bless America, Bill O|||||||O
mailto:-------------------- http://www.----------.com/
Dave Milne wrote:
>
> Read it carefully - I said 5252 rpm. Although I made a small mistake - I
> said a circle of 1 foot diameter and I meant a circle of 1 foot radius.
> As to whether an engine will rev that high or what type of cam it uses to
> get there is immaterial ; it just means that the power and torque curves
> WILL NOT cross each other.
>
> Dave
cross.
God Bless America, Bill O|||||||O
mailto:-------------------- http://www.----------.com/
Dave Milne wrote:
>
> Read it carefully - I said 5252 rpm. Although I made a small mistake - I
> said a circle of 1 foot diameter and I meant a circle of 1 foot radius.
> As to whether an engine will rev that high or what type of cam it uses to
> get there is immaterial ; it just means that the power and torque curves
> WILL NOT cross each other.
>
> Dave
02-26-2006, 03:27 PM
#47
Guest
Posts: n/a
Re: Torque/HP curves
"immaterial"! Make a graph where the torque and horsepower do not
cross.
God Bless America, Bill O|||||||O
mailto:-------------------- http://www.----------.com/
Dave Milne wrote:
>
> Read it carefully - I said 5252 rpm. Although I made a small mistake - I
> said a circle of 1 foot diameter and I meant a circle of 1 foot radius.
> As to whether an engine will rev that high or what type of cam it uses to
> get there is immaterial ; it just means that the power and torque curves
> WILL NOT cross each other.
>
> Dave
cross.
God Bless America, Bill O|||||||O
mailto:-------------------- http://www.----------.com/
Dave Milne wrote:
>
> Read it carefully - I said 5252 rpm. Although I made a small mistake - I
> said a circle of 1 foot diameter and I meant a circle of 1 foot radius.
> As to whether an engine will rev that high or what type of cam it uses to
> get there is immaterial ; it just means that the power and torque curves
> WILL NOT cross each other.
>
> Dave
02-26-2006, 03:27 PM
#48
Guest
Posts: n/a
Re: Torque/HP curves
"immaterial"! Make a graph where the torque and horsepower do not
cross.
God Bless America, Bill O|||||||O
mailto:-------------------- http://www.----------.com/
Dave Milne wrote:
>
> Read it carefully - I said 5252 rpm. Although I made a small mistake - I
> said a circle of 1 foot diameter and I meant a circle of 1 foot radius.
> As to whether an engine will rev that high or what type of cam it uses to
> get there is immaterial ; it just means that the power and torque curves
> WILL NOT cross each other.
>
> Dave
cross.
God Bless America, Bill O|||||||O
mailto:-------------------- http://www.----------.com/
Dave Milne wrote:
>
> Read it carefully - I said 5252 rpm. Although I made a small mistake - I
> said a circle of 1 foot diameter and I meant a circle of 1 foot radius.
> As to whether an engine will rev that high or what type of cam it uses to
> get there is immaterial ; it just means that the power and torque curves
> WILL NOT cross each other.
>
> Dave
02-26-2006, 03:27 PM
#49
Guest
Posts: n/a
Re: Torque/HP curves
"immaterial"! Make a graph where the torque and horsepower do not
cross.
God Bless America, Bill O|||||||O
mailto:-------------------- http://www.----------.com/
Dave Milne wrote:
>
> Read it carefully - I said 5252 rpm. Although I made a small mistake - I
> said a circle of 1 foot diameter and I meant a circle of 1 foot radius.
> As to whether an engine will rev that high or what type of cam it uses to
> get there is immaterial ; it just means that the power and torque curves
> WILL NOT cross each other.
>
> Dave
cross.
God Bless America, Bill O|||||||O
mailto:-------------------- http://www.----------.com/
Dave Milne wrote:
>
> Read it carefully - I said 5252 rpm. Although I made a small mistake - I
> said a circle of 1 foot diameter and I meant a circle of 1 foot radius.
> As to whether an engine will rev that high or what type of cam it uses to
> get there is immaterial ; it just means that the power and torque curves
> WILL NOT cross each other.
>
> Dave
02-26-2006, 03:52 PM
#50
Guest
Posts: n/a
Re: Torque/HP curves
Well they won't cross if the engine won't rev to 5252 rpm !!!
Dave
"L.W. (ßill) ------ III" <----------@***.net> wrote in message
news:44020F29.43C379E9@***.net...
> "immaterial"! Make a graph where the torque and horsepower do not
> cross.
> God Bless America, Bill O|||||||O
> mailto:-------------------- http://www.----------.com/
>
> Dave Milne wrote:
> >
> > Read it carefully - I said 5252 rpm. Although I made a small mistake - I
> > said a circle of 1 foot diameter and I meant a circle of 1 foot radius.
> > As to whether an engine will rev that high or what type of cam it uses
to
> > get there is immaterial ; it just means that the power and torque curves
> > WILL NOT cross each other.
> >
> > Dave
Dave
"L.W. (ßill) ------ III" <----------@***.net> wrote in message
news:44020F29.43C379E9@***.net...
> "immaterial"! Make a graph where the torque and horsepower do not
> cross.
> God Bless America, Bill O|||||||O
> mailto:-------------------- http://www.----------.com/
>
> Dave Milne wrote:
> >
> > Read it carefully - I said 5252 rpm. Although I made a small mistake - I
> > said a circle of 1 foot diameter and I meant a circle of 1 foot radius.
> > As to whether an engine will rev that high or what type of cam it uses
to
> > get there is immaterial ; it just means that the power and torque curves
> > WILL NOT cross each other.
> >
> > Dave